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4x^2=80+x
We move all terms to the left:
4x^2-(80+x)=0
We add all the numbers together, and all the variables
4x^2-(x+80)=0
We get rid of parentheses
4x^2-x-80=0
We add all the numbers together, and all the variables
4x^2-1x-80=0
a = 4; b = -1; c = -80;
Δ = b2-4ac
Δ = -12-4·4·(-80)
Δ = 1281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{1281}}{2*4}=\frac{1-\sqrt{1281}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{1281}}{2*4}=\frac{1+\sqrt{1281}}{8} $
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